(3x+4)(x^2-5x+2)=0

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Solution for (3x+4)(x^2-5x+2)=0 equation: 


Simplifying
(3x + 4)(x2 + -5x + 2) = 0

Reorder the terms:
(4 + 3x)(x2 + -5x + 2) = 0

Reorder the terms:
(4 + 3x)(2 + -5x + x2) = 0

Multiply (4 + 3x) * (2 + -5x + x2)
(4(2 + -5x + x2) + 3x * (2 + -5x + x2)) = 0
((2 * 4 + -5x * 4 + x2 * 4) + 3x * (2 + -5x + x2)) = 0
((8 + -20x + 4x2) + 3x * (2 + -5x + x2)) = 0
(8 + -20x + 4x2 + (2 * 3x + -5x * 3x + x2 * 3x)) = 0
(8 + -20x + 4x2 + (6x + -15x2 + 3x3)) = 0

Reorder the terms:
(8 + -20x + 6x + 4x2 + -15x2 + 3x3) = 0

Combine like terms: -20x + 6x = -14x
(8 + -14x + 4x2 + -15x2 + 3x3) = 0

Combine like terms: 4x2 + -15x2 = -11x2
(8 + -14x + -11x2 + 3x3) = 0

Solving
8 + -14x + -11x2 + 3x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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